85 lines
2.8 KiB
MySQL
85 lines
2.8 KiB
MySQL
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USE Northwind_2020;
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-- 1. Podaj identyfikator najd<6A>u<EFBFBD>ej realizowanego zam<61>wienia
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SELECT OrderID, datediff(DAY, OrderDate, ShippedDate) as Days
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FROM Orders
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ORDER BY Days DESC
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SELECT OrderID, datediff(DAY, OrderDate, ShippedDate) as Days
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FROM Orders
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WHERE datediff(DAY, OrderDate, ShippedDate) =
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(SELECT max(datediff(DAY, OrderDate, ShippedDate)) FROM Orders)
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-- 2. Poda<64> klient<6E>w, kt<6B>rzy mieli przerw<72> w zakupach d<>u<EFBFBD>sz<73> ni<6E> 2 miesi<73>ce
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SELECT OrderID, CustomerID, OrderDate, (
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SELECT TOP 1 OrderDate FROM Orders
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WHERE OrderID > o.OrderID AND
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CustomerID = o.CustomerID
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) AS NextOrderDate,
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datediff(DAY, OrderDate, (
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SELECT TOP 1 OrderDate FROM Orders
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WHERE OrderID > o.OrderID AND
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CustomerID = o.CustomerID
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))
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FROM Orders AS o WHERE datediff(DAY, OrderDate, (
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SELECT TOP 1 OrderDate FROM Orders
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WHERE OrderID > o.OrderID AND
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CustomerID = o.CustomerID
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)) > 62
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-- 3. Wypisa<73> identyfikatory tych pracownik<69>w, kt<6B>rzy realizowali wi<77>cej zam<61>wie<69>
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-- ni<6E> liczba zam<61>wie<69> zrealizowanych przez pracownik<69>w z tego samego kraju
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-- co spedytorzy.
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SELECT EmployeeID, count(OrderID) FROM Orders
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GROUP BY EmployeeID
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HAVING count(OrderID) >= all (
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SELECT count(OrderID) FROM Orders
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INNER JOIN Employees ON Orders.EmployeeID = Employees.EmployeeID
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WHERE Country = ShipCountry
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GROUP BY Orders.EmployeeID
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)
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-- 4. W firmie u<>ywaj<61>cej bazy Northwind pracownicy (tabela Employees) posiadaj<61>
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-- adresy emial<61>owe. Za<5A><61><EFBFBD>my, <20>e standardowo nazwa konta (cz<63><7A><EFBFBD> przed znakiem @)
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-- zbudowana jest z pierwszej litery imienia (firstname), inicja<6A>u <20>rodkowego
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-- (pole middlinitial) oraz pierwszych o<>miu znak<61>w nazwiska (lastname).
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-- Utw<74>rz zapytanie, kt<6B>re wygeneruje te nazwy email<69>owe. W tym zadaniu nale<6C>y
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-- u<>y<EFBFBD> funkcji <20>a<EFBFBD>cuchowych LOWER i SUBSTRING.
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SELECT FirstName, LastName, lower(
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concat(
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substring(FirstName, 1, 1),
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substring(LastName, 1, 8),
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'@northwind.com'
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)
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) FROM Employees
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-- 5. Podaj dzie<69> w kt<6B>rym by<62>o najwi<77>cej zam<61>wie<69>
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SELECT count(OrderID) AS HowMany, datename(weekday, OrderDate) AS WeekDay
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FROM Orders
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GROUP BY datename(weekday, OrderDate)
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ORDER BY count(OrderID) DESC
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-- 6. Wypisz nazw<7A> i adres najcz<63><7A>ciej zamawiaj<61>cego klienta -- broken
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SELECT CompanyName, City
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FROM Customers
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WHERE CompanyName = (
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SELECT CompanyName FROM Customers
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INNER JOIN Orders ON Orders.CustomerID = Customers.CustomerID
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HAVING count(OrderID) >= ALL (SELECT count(OrderID) FROM Orders GROUP BY CustomerID)
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)
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SELECT count(OrderID), Orders.CustomerID
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FROM Orders
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INNER JOIN Customers ON Customers.CustomerID = Orders.CustomerID
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GROUP BY Orders.CustomerID
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-- 7. Wskaza<7A> pracownika kt<6B>ry obs<62>ugiwa<77> klienta, kt<6B>rego nie obs<62>ugiwa<77> nikt inny
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-- 8. Wypisz dane pracownika kt<6B>rego nazwisko jest najd<6A>u<EFBFBD>sze. Skorzystaj z funkcji LEN
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SELECT LastName
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FROM Employees
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WHERE len(LastName) = (SELECT max(len(LastName)) FROM Employees)
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